摘要
为探讨Ⅱ级试验防雷SPD(浪涌保护器)的最大放电电流I_(max)(8/20μs)值与Ⅰ级试验防雷SPD的冲击电流I_(imp)(10/350μs)值之间的等效关系,采用将I_(max)(8/20μs)电流波和I_(imp)(10/350μs)电流波分别等效为斜角波的方法,分别计算Ⅱ级试验SPD承受的I_(max)(8/20μs)电流波能量和Ⅰ级试验SPD承受的I_(imp)(10/350μs)电流波能量,令两者的能量相等,分析计算出I_(max)(8/20μs)和I_(imp)(10/350μs)应满足的比值关系。通过分析计算得出:当Ⅱ级试验SPD的电压保护水平值与Ⅰ级试验SPD的电压保护水平值相等时,Ⅱ级试验SPD的最大放电电流I_(max)(8/20μs)值为Ⅰ级试验SPD的冲击电流I_(imp)(10/350μs)值的21.56倍,两者所能承受的能量大致相等。
In order to study the equivalent relation between the maximum discharge currents(I_(max))of two types of SPDs(Class-Ⅱtest and Class-Ⅰ test),the paper uses the method of taking I_(max)(8/20μs)and I_(imp)(10/35μs)current waves as oblique waves,and calculates the I_(max)(8/20μs)current wave energy exerted on the Class-Ⅱ test SPD and I_(imp)(10/350μs)current wave energy exerted on the Class-Ⅰtest SPD,equals the energy of the two,then calculates the ratio of I_(max)(8/20μs)and I_(imp)(10/350μs),both of which should be satisfied.It is concluded through the calculation that when the voltage protection level of Class-Ⅱtest SPD is equal to that of Class-Ⅰtest SPD and the Class-Ⅱ test SPD maximum discharge current is 21.56 times as much as that of Class-Ⅰtest SPD,the both bear the same energy.
出处
《气象科技》
北大核心
2017年第2期405-408,共4页
Meteorological Science and Technology