期刊文献+

原创“剩余倍分法”(续)——重解“中国剩余定理”

Original"surplus time of law" substitution"Chinese remainder theorem"
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摘要 五、用方法一、方法二、方法三、公式、解四个例题例1方法一、方法二:解一次同余方程组,同式(1)、(3)、(2) The integer aliquot surplus question appearance and the general solution, cause the people one of mathematics questions which seeks with hardship.Already appears with this similar surplus question in the A.D. 4, about 5 centuries"Grandson Calculatedafter" in, people classifies the surplus question to "the Chinese Remainder theorem"under name, appears in"Theory of numbers"in mathematics domain.This article in the foundation which analyzes to "the Chinese Remainder theorem", gives one kind easily, easy to study easy to understand, may popularize the application the new method, substitutes "the Chinese Remainder theorem".
出处 《数学爱好者(高考版)》 2008年第12期52-55,共4页
关键词 Derives the FORMULA the FOUNDATION NUMBER TIME of Derives the formula the foundation number time of fraction odd one the few solution new method.
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