摘要
目的:以小鼠饲料正常脂肪摄入量7.84%为基础,比较不同脂肪酸构成比对小鼠血脂水平的影响。方法:以小鼠正常饲料脂肪及脂肪酸构成为对照,分别设S/M/P比值为1∶1.7∶1.2和1∶1∶1的饲料,其中n-6/n-3比值在1~10∶1各设计4组,共10组, 喂小鼠10 w,测定血脂水平。结果: S/M/P为1∶1.7∶1.2, n-6/n-3在1~5∶1时TC和TC/HDL-C水平显著低于8∶1和10∶1组(P<0.05); S/M/P为1∶1∶1,n-6/n-3为1∶1时的TC和LDL-C水平显著低于其余各比值组(P<0.05);当n-6/n-3为10∶1时,S/M/P为1∶1.7∶1.2的TC、LDL-C、HDL-C以及TC/HDL-C和LDL-C/HDL-C水平均显著低于1∶1∶2组(P<0.05),S/M/P为1∶1∶2的LDL-C和TC/HDL-C水平显著低于1∶1∶1组(P<0.05)。结论: S/M/P现状1∶1.7∶1.2时,n-6/n-3在1~5∶1可维持血脂在较低水平;如脂肪酸构成比为1∶1∶1时,维持较低血脂所需的n-6/n-3为1∶1;在现状膳食n-6/n-3为10∶1时,S/M/P在1∶1.7∶1.2有利于维持低血脂。
Objective: To study the effect of different ratios of n-6 to n-3 polyunsaturated fatty acid on serum lipid in mice, on the premise that the ratio of SFA to MUFA to PUFA is 1∶1.7∶1.2 or 1∶1∶1. Methods: Ten experimental diets were made from six oils different in fatty acid composition to raise the mice for 10 w. Then the blood lipids were determined in mice fed with different experimental diets. Results and conclusion: Based on the ratio of S/M/P 1∶1.7∶1.2, which is the current dietary fatty acid intake, n-6/n-3 at 1~5∶1 will have lower serum lipid level. Based on the ratio of S/M/P 1∶1∶1 , n-6/n-3 at 1∶1 will have lower serum lipid level. Based on the ratio of n-6 /n-3 10∶1 which is the current dietary fatty acid composition abroad , S/M/P 1∶1.7∶1.2 will have lower serum lipid level.
出处
《营养学报》
CAS
CSCD
北大核心
2004年第1期5-8,共4页
Acta Nutrimenta Sinica