In this note, we shall prove an interesting result.Theorem. Let 2 be a piece of surface without an umbilical point in 3-dimensional constant curvature space M<sup>3</sup>(C) and possess a constant mean c...In this note, we shall prove an interesting result.Theorem. Let 2 be a piece of surface without an umbilical point in 3-dimensional constant curvature space M<sup>3</sup>(C) and possess a constant mean curvature C<sub>1</sub> (C<sub>1</sub>】0). ∑ can be isometric to a piece of the surface ∑<sup>*</sup> without an umbilical point, ∑<sup>*</sup> owning a constant mean curvature C<sub>2</sub>(C<sub>2</sub>】0 and C<sub>1</sub>≠C<sub>2</sub>) in M<sup>3</sup>(C)展开更多
Given some function H(X),one can find a compact hypersurface in S<sup>n+1</sup>,which ishomeomorphic to S<sup>m</sup>(1)×S<sup>n-m</sup>(1)and whose mean curvature is giv...Given some function H(X),one can find a compact hypersurface in S<sup>n+1</sup>,which ishomeomorphic to S<sup>m</sup>(1)×S<sup>n-m</sup>(1)and whose mean curvature is given by H(X).展开更多
文摘In this note, we shall prove an interesting result.Theorem. Let 2 be a piece of surface without an umbilical point in 3-dimensional constant curvature space M<sup>3</sup>(C) and possess a constant mean curvature C<sub>1</sub> (C<sub>1</sub>】0). ∑ can be isometric to a piece of the surface ∑<sup>*</sup> without an umbilical point, ∑<sup>*</sup> owning a constant mean curvature C<sub>2</sub>(C<sub>2</sub>】0 and C<sub>1</sub>≠C<sub>2</sub>) in M<sup>3</sup>(C)
文摘Given some function H(X),one can find a compact hypersurface in S<sup>n+1</sup>,which ishomeomorphic to S<sup>m</sup>(1)×S<sup>n-m</sup>(1)and whose mean curvature is given by H(X).