Solution of ferric nitrate was obtained from industrial iron based on the following equation Fe+4HNO3→Fe(NO3)3+NO+H2O and 2NO+O2→2NO2. Fe-Cu-K-Si catalysts were prepared in a continuous precipitation reactor. Perf...Solution of ferric nitrate was obtained from industrial iron based on the following equation Fe+4HNO3→Fe(NO3)3+NO+H2O and 2NO+O2→2NO2. Fe-Cu-K-Si catalysts were prepared in a continuous precipitation reactor. Performance of No.16 catalyst prepared from Q-235 carbon steel is the best among three industrial irons: iron sheet, iron powder and Q-235. In the range of 265℃~276℃, 1.5MPa~1.6MPa, H2/CO 0.68~1.0 and WHSV 3.6L/g·h~4.2L/g·h, the mean values of xH2+CO and C+5 are 68.7% and 96.7g·m-3 in the evaluation test of 432h. Performance of No.16 catalyst being lower than that of No.9 catalyst is due to effect of poison of P,S contained in industrial iron Q-235.展开更多
采用完全液相法制备了Cu-Zn-S i-A l浆状二甲醚合成催化剂,分析研究了其在浆态床合成气一步法合成二甲醚过程中的失活现象和机理.采用X射线粉末衍射、N2吸附测试、X射线光电子能谱以及元素分析等表征方法对催化剂使用前后的变化情况进...采用完全液相法制备了Cu-Zn-S i-A l浆状二甲醚合成催化剂,分析研究了其在浆态床合成气一步法合成二甲醚过程中的失活现象和机理.采用X射线粉末衍射、N2吸附测试、X射线光电子能谱以及元素分析等表征方法对催化剂使用前后的变化情况进行了分析.结果表明,完全液相法制备的Cu-Zn-S i-A l浆状催化剂的失活与传统方法制备的催化剂不尽相同,没有发现催化剂Cu晶粒的长大和比表面积降低等失活因素;催化剂失活与S i的存在有关,Cu组分的流失是其失活的主要原因.展开更多
文摘Solution of ferric nitrate was obtained from industrial iron based on the following equation Fe+4HNO3→Fe(NO3)3+NO+H2O and 2NO+O2→2NO2. Fe-Cu-K-Si catalysts were prepared in a continuous precipitation reactor. Performance of No.16 catalyst prepared from Q-235 carbon steel is the best among three industrial irons: iron sheet, iron powder and Q-235. In the range of 265℃~276℃, 1.5MPa~1.6MPa, H2/CO 0.68~1.0 and WHSV 3.6L/g·h~4.2L/g·h, the mean values of xH2+CO and C+5 are 68.7% and 96.7g·m-3 in the evaluation test of 432h. Performance of No.16 catalyst being lower than that of No.9 catalyst is due to effect of poison of P,S contained in industrial iron Q-235.
文摘采用完全液相法制备了Cu-Zn-S i-A l浆状二甲醚合成催化剂,分析研究了其在浆态床合成气一步法合成二甲醚过程中的失活现象和机理.采用X射线粉末衍射、N2吸附测试、X射线光电子能谱以及元素分析等表征方法对催化剂使用前后的变化情况进行了分析.结果表明,完全液相法制备的Cu-Zn-S i-A l浆状催化剂的失活与传统方法制备的催化剂不尽相同,没有发现催化剂Cu晶粒的长大和比表面积降低等失活因素;催化剂失活与S i的存在有关,Cu组分的流失是其失活的主要原因.