To obtain the coupling characteristics between slab wave-guides including left-handed material,we modify the coupled wave equations by using Maxwell’s equations. First,we obtain new-coupled wave equations and new-cou...To obtain the coupling characteristics between slab wave-guides including left-handed material,we modify the coupled wave equations by using Maxwell’s equations. First,we obtain new-coupled wave equations and new-coupling coefficient. Second,the coupling between two identical five-layer slab wave-guides where their cores are left-handed material,but their claddings are right-handed materials is studied. The coupling coefficient for even TE mode which is more complex than that of the riglt-handed material slab wave guides,is obtained.展开更多
题目:如图1所示,在光滑的水平面上有一辆长L=1.0米的小车 A,A 上有一木块 B（大小不计可视为质点）,A 与 B 的质量相等,B 与 A 的滑动摩擦系数为μ=0.05。开始时 A 静止,B 位于 A 的正中央以速度v<sub>0</sub>=5.0米/秒向...题目:如图1所示,在光滑的水平面上有一辆长L=1.0米的小车 A,A 上有一木块 B（大小不计可视为质点）,A 与 B 的质量相等,B 与 A 的滑动摩擦系数为μ=0.05。开始时 A 静止,B 位于 A 的正中央以速度v<sub>0</sub>=5.0米/秒向右运动。假设 B 与 A 的前后两壁碰撞是完全弹性的。求 B 与 A 的前、后壁最多能相碰多少次?从开始到 B 与 A 的最后一次碰撞时 A 运动的总距离是多少?此题选自《北京市海淀区1990年5月期中练习物理试卷》,本文略有改动。本人试用速度—时间图象即 v-t 图象很简单地解决了这一问题。我们知道,开始物体 B 向右运动,由于摩擦力的存在,A 被带动向右作加速运动,B 亦作减速运动,到 B 与A的右壁碰前,有 v<sub>B1</sub>】v<sub>A1</sub>。由于 A、B 质量相等且碰撞是完全弹性的,故碰后二者速度交换,得 v<sub>A′1</sub>=v<sub>B1</sub>,展开更多
基金Creative Graduate Student Foundation of Shanghai University (A.16-0107-07-001)
文摘To obtain the coupling characteristics between slab wave-guides including left-handed material,we modify the coupled wave equations by using Maxwell’s equations. First,we obtain new-coupled wave equations and new-coupling coefficient. Second,the coupling between two identical five-layer slab wave-guides where their cores are left-handed material,but their claddings are right-handed materials is studied. The coupling coefficient for even TE mode which is more complex than that of the riglt-handed material slab wave guides,is obtained.
文摘题目:如图1所示,在光滑的水平面上有一辆长L=1.0米的小车 A,A 上有一木块 B（大小不计可视为质点）,A 与 B 的质量相等,B 与 A 的滑动摩擦系数为μ=0.05。开始时 A 静止,B 位于 A 的正中央以速度v<sub>0</sub>=5.0米/秒向右运动。假设 B 与 A 的前后两壁碰撞是完全弹性的。求 B 与 A 的前、后壁最多能相碰多少次?从开始到 B 与 A 的最后一次碰撞时 A 运动的总距离是多少?此题选自《北京市海淀区1990年5月期中练习物理试卷》,本文略有改动。本人试用速度—时间图象即 v-t 图象很简单地解决了这一问题。我们知道,开始物体 B 向右运动,由于摩擦力的存在,A 被带动向右作加速运动,B 亦作减速运动,到 B 与A的右壁碰前,有 v<sub>B1</sub>】v<sub>A1</sub>。由于 A、B 质量相等且碰撞是完全弹性的,故碰后二者速度交换,得 v<sub>A′1</sub>=v<sub>B1</sub>,
