Compound C28O4H50·3H2O(Mr = 504. 74) is the orthorhombic space group P212121,wilh a=8. 244(3),b=9. 957(2),c=36. 442(3) A ,V=2991. 4 A3,Z = 4,Dc=1. 123g/cm3,and F(000) = 1120. The structure was solved by direct me...Compound C28O4H50·3H2O(Mr = 504. 74) is the orthorhombic space group P212121,wilh a=8. 244(3),b=9. 957(2),c=36. 442(3) A ,V=2991. 4 A3,Z = 4,Dc=1. 123g/cm3,and F(000) = 1120. The structure was solved by direct methods and refined by full-matrix least-squares to R=0. 064 for 2029 independent reflections with I≥1σ(I). The results showed that the basic structure of C28C4H50 is a 4-carboatomic ring -3 - terpene. There are three water molecules in an asymmetric unit.展开更多
文摘Compound C28O4H50·3H2O(Mr = 504. 74) is the orthorhombic space group P212121,wilh a=8. 244(3),b=9. 957(2),c=36. 442(3) A ,V=2991. 4 A3,Z = 4,Dc=1. 123g/cm3,and F(000) = 1120. The structure was solved by direct methods and refined by full-matrix least-squares to R=0. 064 for 2029 independent reflections with I≥1σ(I). The results showed that the basic structure of C28C4H50 is a 4-carboatomic ring -3 - terpene. There are three water molecules in an asymmetric unit.