如权对(u,v)∈S_p(1<p<∞),即intergral from G [(v^(1-p′)X_(?))~*(x)]~p u(x)dx≤C integral from Q v(x)^(1-p′)dx<+∞ (?)Q(?)R^n,则存在(u_1,v_1),(u_2,v_2)∈A_1~*,即u_1~*(x)≤Cv_1(x),u_2~*(x)≤Cv_2(x) a.e.,使 u(x...如权对(u,v)∈S_p(1<p<∞),即intergral from G [(v^(1-p′)X_(?))~*(x)]~p u(x)dx≤C integral from Q v(x)^(1-p′)dx<+∞ (?)Q(?)R^n,则存在(u_1,v_1),(u_2,v_2)∈A_1~*,即u_1~*(x)≤Cv_1(x),u_2~*(x)≤Cv_2(x) a.e.,使 u(x)=u_1(x)v_2(x)^(1-p),v(x)=u_2(x)^(1-p)v_1(x),这里常数 C>0,f~*(x)是 f 的 Hardy-Littlewood 极大函数。展开更多
文摘如权对(u,v)∈S_p(1<p<∞),即intergral from G [(v^(1-p′)X_(?))~*(x)]~p u(x)dx≤C integral from Q v(x)^(1-p′)dx<+∞ (?)Q(?)R^n,则存在(u_1,v_1),(u_2,v_2)∈A_1~*,即u_1~*(x)≤Cv_1(x),u_2~*(x)≤Cv_2(x) a.e.,使 u(x)=u_1(x)v_2(x)^(1-p),v(x)=u_2(x)^(1-p)v_1(x),这里常数 C>0,f~*(x)是 f 的 Hardy-Littlewood 极大函数。
基金Supported by National and Zhejiang Provincial Foundation of China,Supported Partly the Ministry of Education Doctoral Foundation(Grant:No.10771188,No.Y606117,No.20060335133).