Let (S, ≤) be a strictly totally ordered monoid, and M and N be left R modules. We show the following results: (1) If (S, ≤) is finitely generated and satisfies the condition that 0≤S for any s ∈S, then Epi([[RS,...Let (S, ≤) be a strictly totally ordered monoid, and M and N be left R modules. We show the following results: (1) If (S, ≤) is finitely generated and satisfies the condition that 0≤S for any s ∈S, then Epi([[RS,≤]][[MS,≤]]) = Epi([[RS,≤]][[NS,≤]]) if and only if Epi(M) = Epi(N); (2) If (S,≤) is artinian, then Mono([[RS,≤]][MS,≤])= Mono([[RS,≤]][NS,≤]) if and only if Mono(M) = Mono(N).展开更多
文摘Let (S, ≤) be a strictly totally ordered monoid, and M and N be left R modules. We show the following results: (1) If (S, ≤) is finitely generated and satisfies the condition that 0≤S for any s ∈S, then Epi([[RS,≤]][[MS,≤]]) = Epi([[RS,≤]][[NS,≤]]) if and only if Epi(M) = Epi(N); (2) If (S,≤) is artinian, then Mono([[RS,≤]][MS,≤])= Mono([[RS,≤]][NS,≤]) if and only if Mono(M) = Mono(N).
