1 The Operator（-△）<sup>1/2</sup> In Ref.[1], we define the operator （-△）<sup>1/2</sup> on the Banach space L<sup>p</sup>（R<sup>n</sup>） as follows:（-△）<sup...1 The Operator（-△）<sup>1/2</sup> In Ref.[1], we define the operator （-△）<sup>1/2</sup> on the Banach space L<sup>p</sup>（R<sup>n</sup>） as follows:（-△）<sup>1/2</sup>sum from j=1 to n R<sub>j</sub> D<sub>j</sub>, its展开更多
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文摘1 The Operator（-△）<sup>1/2</sup> In Ref.[1], we define the operator （-△）<sup>1/2</sup> on the Banach space L<sup>p</sup>（R<sup>n</sup>） as follows:（-△）<sup>1/2</sup>sum from j=1 to n R<sub>j</sub> D<sub>j</sub>, its
