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Pythagorician Divisors and Applications to Some Diophantine Equations
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作者 François Emmanuel Tanoé Prosper Kouadio Kimou 《Advances in Pure Mathematics》 2023年第2期35-70,共36页
We consider the Pythagoras equation X<sup>2</sup> +Y<sup>2</sup> = Z<sup>2</sup>, and for any solution of the type (a,b = 2<sup>s</sup>b<sub>1 </sub>≠0,c) ... We consider the Pythagoras equation X<sup>2</sup> +Y<sup>2</sup> = Z<sup>2</sup>, and for any solution of the type (a,b = 2<sup>s</sup>b<sub>1 </sub>≠0,c) ∈ N<sup>*3</sup>, s ≥ 2, b<sub>1</sub>odd, (a,b,c) ≡ (±1,0,1)(mod 4), c > a , c > b, and gcd(a,b,c) = 1, we then prove the Pythagorician divisors Theorem, which results in the following: , where (d,d′′) (resp. (e,e<sup>n</sup>)) are unique particular divisors of a and b, such that a = dd′′ (resp. b = ee′′ ), these divisors are called: Pythagorician divisors from a, (resp. from b). Let’s put λ ∈{0,1}, defined by: and S = s -λ (s -1). Then such that . Moreover the map is a bijection. We apply this new tool to obtain a new classification of the primitive, positive and non-trivial solutions of the Pythagoras equations: a<sup>2</sup> + b<sup>2</sup> = c<sup>2</sup> via the Pythagorician parameters (d,e,S ). We obtain for (d, e) fixed, the equivalence class of any Pythagorician solution (a,b,c), checking , namely: . We also update the solutions of some Diophantine equations of degree 2, already known, but very important for the resolution of other equations. With this tool of Pythagorean divisors, we have obtained (in another paper) new recurrent methods to solve Fermat’s equation: a<sup>4</sup> + b<sup>4 </sup>= c<sup>4</sup>, other than usual infinite descent method;and to solve congruent numbers problem. We believe that this tool can bring new arguments, for Diophantine resolution, of the general equations of Fermat: a<sup>2p</sup> + b<sup>2p</sup> = c<sup>2p</sup> and a<sup>p</sup> + b<sup>p</sup> = c<sup>p</sup>. MSC2020-Mathematical Sciences Classification System: 11A05-11A51-11D25-11D41-11D72. 展开更多
关键词 Pythagoras Equation Pythagorician Triplets diophantine equations of Degree 2 Factorisation-Gcd-Fermat’s equations
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A Kind of Diophantine Equations in Finite Simple Groups 被引量:3
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作者 曹珍富 《Northeastern Mathematical Journal》 CSCD 2000年第4期391-397,共7页
In this paper, we prove that if p, q are distinct primes, (p,q)≡(1,7) (mod 12) and Legendres symbol pq=1 , then the equation 1+p a=2 bq c+2 dp eq f has only solutions of the form (a,b,c,d,e,f)=... In this paper, we prove that if p, q are distinct primes, (p,q)≡(1,7) (mod 12) and Legendres symbol pq=1 , then the equation 1+p a=2 bq c+2 dp eq f has only solutions of the form (a,b,c,d,e,f)=(t,0,0,0,t,0), where t is a non negative integer. We also give all solutions of a kind of generalized Ramanujan Nagell equations by using the theories of imaginary quadratic field and Pells equation. 展开更多
关键词 exponential diophantine equation generalized Ramanujan Nagell equation finite simple group difference set
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Non-Negative Integer Solutions of Two Diophantine Equations 2x + 9y = z2 and 5x + 9y = z2
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作者 Md. Al-Amin Khan Abdur Rashid Md. Sharif Uddin 《Journal of Applied Mathematics and Physics》 2016年第4期762-765,共4页
In this paper, we study two Diophantine equations of the type p<sup>x</sup> + 9<sup>y</sup> = z<sup>2</sup> , where p is a prime number. We find that the equation 2<sup>x</... In this paper, we study two Diophantine equations of the type p<sup>x</sup> + 9<sup>y</sup> = z<sup>2</sup> , where p is a prime number. We find that the equation 2<sup>x</sup> + 9<sup>y</sup> = z<sup>2</sup> has exactly two solutions (x, y, z) in non-negative integer i.e., {(3, 0, 3),(4, 1, 5)} but 5<sup>x</sup> + 9<sup>y</sup> = z<sup>2</sup> has no non-negative integer solution. 展开更多
关键词 Exponential diophantine Equation Integer Solutions
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Diophantine Equations and the Freeness of Mobius Groups
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作者 Marin Gutan 《Applied Mathematics》 2014年第10期1400-1411,共12页
Let p and q be two fixed non zero integers verifying the condition gcd(p,q) = 1. We check solutions in non zero integers a1,b1,a2,b2 and a3 for the following Diophantine equations: (B1) (B2) . The equations (B1) and (... Let p and q be two fixed non zero integers verifying the condition gcd(p,q) = 1. We check solutions in non zero integers a1,b1,a2,b2 and a3 for the following Diophantine equations: (B1) (B2) . The equations (B1) and (B2) were considered by R.C. Lyndon and J.L. Ullman in [1] and A.F. Beardon in [2] in connection with the freeness of the M?bius group generated by two matrices of namely and where .?They proved that if one of the equations (B1) or (B2) has solutions in non zero integers then the group is not free. We give algorithms to decide if these equations admit solutions. We obtain an arithmetical criteria on p and q for which (B1) admits solutions. We show that for all p and q the equations (B1) and (B2) have only a finite number of solutions. 展开更多
关键词 diophantine Equation Mobius Groups Free Group
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Diophantine Quotients and Remainders with Applications to Fermat and Pythagorean Equations
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作者 Prosper Kouadio Kimou François Emmanuel Tanoé 《American Journal of Computational Mathematics》 2023年第1期199-210,共12页
Diophantine equations have always fascinated mathematicians about existence, finitude, and the calculation of possible solutions. Among these equations, one of them will be the object of our research. This is the Pyth... Diophantine equations have always fascinated mathematicians about existence, finitude, and the calculation of possible solutions. Among these equations, one of them will be the object of our research. This is the Pythagoras’- Fermat’s equation defined as follows.                                                                                         (1) when , it is well known that this equation has an infinity of solutions but has none (non-trivial) when . We also know that the last result, named Fermat-Wiles theorem (or FLT) was obtained at great expense and its understanding remains out of reach even for a good fringe of professional mathematicians. The aim of this research is to set up new simple but effective tools in the treatment of Diophantine equations and that of Pythagoras-Fermat. The tools put forward in this research are the properties of the quotients and the Diophantine remainders which we define as follows. Let a non-trivial triplet () solution of Equation (1) such that . and are called the Diophantine quotients and remainders of solution . We compute the remainder and the quotient of b and c by a using the division algorithm. Hence, we have: and et with . We prove the following important results. if and only if and if and only if . Also, we deduce that or for any hypothetical solution . We illustrate these results by effectively computing the Diophantine quotients and remainders in the case of Pythagorean triplets using a Python program. In the end, we apply the previous properties to directly prove a partial result of FLT. . 展开更多
关键词 diophantine Equation Modular Arithmetic Fermat-Wiles Theorem Pythagorean Triplets Division Theorem Division Algorithm Python Program diophantine Quotients diophantine Remainders
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Inductive Rings and Systems of Diophantine Equations
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作者 Rong Fang BIE Shi Qiang WANG 《Acta Mathematica Sinica,English Series》 SCIE CSCD 2006年第5期1549-1556,共8页
In this paper, by using model-theoretic methods, it is shown that some systems of unsolved cubic diophantine equations in number theory can have solutions in certain inductive extension rings of the ring I of rational... In this paper, by using model-theoretic methods, it is shown that some systems of unsolved cubic diophantine equations in number theory can have solutions in certain inductive extension rings of the ring I of rational integers. These inductive rings are not fields, and every element of them is a sum of 4 cubes and a sum of 3 squares. Also some of them satisfy the Goldbach conjecture and some others don't. 展开更多
关键词 Inductive rings Systems of unsolved cubic diophantine equations Model theory
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On the solutions of a system of two Diophantine equations 被引量:4
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作者 LUO JiaGui YUAN PingZhi 《Science China Mathematics》 SCIE 2014年第7期1401-1418,共18页
We obtain all positive integer solutions(m1,m2,a,b) with a &gt; b,gcd(a,b) = 1 to the system of Diophantine equations km21- lat1bt2a2r= C1,km22- lat1bt2b2r= C2,with C1,C2 ∈ {-1,1,-2,2,-4,4},and k,l,t1,t2,r ∈ Z ... We obtain all positive integer solutions(m1,m2,a,b) with a &gt; b,gcd(a,b) = 1 to the system of Diophantine equations km21- lat1bt2a2r= C1,km22- lat1bt2b2r= C2,with C1,C2 ∈ {-1,1,-2,2,-4,4},and k,l,t1,t2,r ∈ Z such that k &gt; 0,l &gt; 0,r &gt; 0,t1 &gt; 0,t2 0,gcd(k,l) = 1,and k is square-free. 展开更多
关键词 minimal solution fundamental solution Jacobi symbol diophantine equation
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Solving Multivariate Polynomial Matrix Diophantine Equations with Gr?bner Basis Method
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作者 XIAO Fanghui LU Dong WANG Dingkang 《Journal of Systems Science & Complexity》 SCIE EI CSCD 2022年第1期413-426,共14页
Different from previous viewpoints,multivariate polynomial matrix Diophantine equations are studied from the perspective of modules in this paper,that is,regarding the columns of matrices as elements in modules.A nece... Different from previous viewpoints,multivariate polynomial matrix Diophantine equations are studied from the perspective of modules in this paper,that is,regarding the columns of matrices as elements in modules.A necessary and sufficient condition of the existence for the solution of equations is derived.Using powerful features and theoretical foundation of Gr?bner bases for modules,the problem for determining and computing the solution of matrix Diophantine equations can be solved.Meanwhile,the authors make use of the extension on modules for the GVW algorithm that is a signature-based Gr?bner basis algorithm as a powerful tool for the computation of Gr?bner basis for module and the representation coefficients problem directly related to the particular solution of equations.As a consequence,a complete algorithm for solving multivariate polynomial matrix Diophantine equations by the Gr?bner basis method is presented and has been implemented on the computer algebra system Maple. 展开更多
关键词 Gr?bner basis matrix diophantine equation MODULE multivariate polynomial
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The Relationship between the Nonexistence of Generalized Bent Functions and Diophantine Equations
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作者 Feng Mei LIU Qin YUE 《Acta Mathematica Sinica,English Series》 SCIE CSCD 2011年第6期1173-1186,共14页
Two new results on the nonexistence of generalized bent functions are presented by using properties of the decomposition law of primes in cyclotomic fields and properties of solutions of some Diophantine equations, an... Two new results on the nonexistence of generalized bent functions are presented by using properties of the decomposition law of primes in cyclotomic fields and properties of solutions of some Diophantine equations, and examples satisfying our results are given. 展开更多
关键词 Generalized bent function integral basis diophantine equation
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Fermat and Pythagoras Divisors for a New Explicit Proof of Fermat’s Theorem:a4 + b4 = c4. Part I
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作者 Prosper Kouadio Kimou François Emmanuel Tanoé Kouassi Vincent Kouakou 《Advances in Pure Mathematics》 2024年第4期303-319,共17页
In this paper we prove in a new way, the well known result, that Fermat’s equation a<sup>4</sup> + b<sup>4</sup> = c<sup>4</sup>, is not solvable in ℕ , when abc≠0 . To show this ... In this paper we prove in a new way, the well known result, that Fermat’s equation a<sup>4</sup> + b<sup>4</sup> = c<sup>4</sup>, is not solvable in ℕ , when abc≠0 . To show this result, it suffices to prove that: ( F 0 ): a 1 4 + ( 2 s b 1 ) 4 = c 1 4 , is not solvable in ℕ , (where a 1 , b 1 , c 1 ∈2ℕ+1 , pairwise primes, with necessarly 2≤s∈ℕ ). The key idea of our proof is to show that if (F<sub>0</sub>) holds, then there exist α 2 , β 2 , γ 2 ∈2ℕ+1 , such that ( F 1 ): α 2 4 + ( 2 s−1 β 2 ) 4 = γ 2 4 , holds too. From where, one conclude that it is not possible, because if we choose the quantity 2 ≤ s, as minimal in value among all the solutions of ( F 0 ) , then ( α 2 ,2 s−1 β 2 , γ 2 ) is also a solution of Fermat’s type, but with 2≤s−1<s , witch is absurd. To reach such a result, we suppose first that (F<sub>0</sub>) is solvable in ( a 1 ,2 s b 1 , c 1 ) , s ≥ 2 like above;afterwards, proceeding with “Pythagorician divisors”, we creat the notions of “Fermat’s b-absolute divisors”: ( d b , d ′ b ) which it uses hereafter. Then to conclude our proof, we establish the following main theorem: there is an equivalence between (i) and (ii): (i) (F<sub>0</sub>): a 1 4 + ( 2 s b 1 ) 4 = c 1 4 , is solvable in ℕ , with 2≤s∈ℕ , ( a 1 , b 1 , c 1 )∈ ( 2ℕ+1 ) 3 , coprime in pairs. (ii) ∃( a 1 , b 1 , c 1 )∈ ( 2ℕ+1 ) 3 , coprime in pairs, for wich: ∃( b ′ 2 , b 2 , b ″ 2 )∈ ( 2ℕ+1 ) 3 coprime in pairs, and 2≤s∈ℕ , checking b 1 = b ′ 2 b 2 b ″ 2 , and such that for notations: S=s−λ( s−1 ) , with λ∈{ 0,1 } defined by c 1 − a 1 2 ≡λ( mod2 ) , d b =gcd( 2 s b 1 , c 1 − a 1 )= 2 S b 2 and d ′ b = 2 s−S b ′ 2 = 2 s B 2 d b , where ( 2 s B 2 ) 2 =gcd( b 1 2 , c 1 2 − a 1 2 ) , the following system is checked: { c 1 − a 1 = d b 4 2 2+λ = 2 2−λ ( 2 S−1 b 2 ) 4 c 1 + a 1 = 2 1+λ d ′ b 4 = 2 1+λ ( 2 s−S b ′ 2 ) 4 c 1 2 + a 1 2 =2 b ″ 2 4;and this system implies: ( b 1−λ,2 4 ) 2 + ( 2 4s−3 b λ,2 4 ) 2 = ( b ″ 2 2 ) 2;where: ( b 1−λ,2 , b λ,2 , b ″ 2 )={ ( b ′ 2 , b 2 , b ″ 2 )  if λ=0 ( b 2 , b ′ 2 , b ″ 2 )  if λ=1;From where, it is quite easy to conclude, following the method explained above, and which thus closes, part I, of this article. . 展开更多
关键词 Factorisation in Greatest Common Divisor Pythagoras Equation Pythagorician Triplets Fermat's equations Pythagorician Divisors Fermat's Divisors diophantine equations of Degree 2 4-Integral Closure of in
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A Note on Diophantine Equation Ax^4+ 1 = By^2 and Erds' Conjecture on Combinatorial Number
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作者 曹珍富 《Journal of Harbin Institute of Technology(New Series)》 EI CAS 1998年第2期1-3,共3页
A necessary and suffcient condition is given for the equation Ax4+ 1 =By2 to have positive integer solution, and an effective method is derived for solving equation a2x4 + 1 = By2 in positive integers x, y for given h... A necessary and suffcient condition is given for the equation Ax4+ 1 =By2 to have positive integer solution, and an effective method is derived for solving equation a2x4 + 1 = By2 in positive integers x, y for given ho and B completely. Also, using a recently result of Ribet, Darmon and Merel, we proved that Erdos’ conjecture on combinatorial number is right. 展开更多
关键词 diophantine equations SEQUENCE combinatorial number
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Three- and Four-Dimensional Generalized Pythagorean Numbers
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作者 Alfred Wünsche 《Advances in Pure Mathematics》 2024年第1期1-15,共15页
The Pythagorean triples (a, b | c) of planar geometry which satisfy the equation a<sup>2</sup>+b<sup>2</sup>=c<sup>2</sup> with integers (a, b, c) are generalized to 3D-Pythagorean ... The Pythagorean triples (a, b | c) of planar geometry which satisfy the equation a<sup>2</sup>+b<sup>2</sup>=c<sup>2</sup> with integers (a, b, c) are generalized to 3D-Pythagorean quadruples (a, b, c | d) of spatial geometry which satisfy the equation a<sup>2</sup>+b<sup>2</sup>+c<sup>2</sup>=d<sup>2</sup> with integers (a, b, c, d). Rules for a parametrization of the numbers (a, b, c, d) are derived and a list of all possible nonequivalent cases without common divisors up to d<sup>2</sup> is established. The 3D-Pythagorean quadruples are then generalized to 4D-Pythagorean quintuples (a, b, c, d | e) which satisfy the equation a<sup>2</sup>+b<sup>2</sup>+c<sup>2</sup>+d<sup>2</sup>=e<sup>2</sup> and a parametrization is derived. Relations to the 4-square identity are discussed which leads also to the N-dimensional case. The initial 3D- and 4D-Pythagorean numbers are explicitly calculated up to d<sup>2</sup>, respectively, e<sup>2</sup>. 展开更多
关键词 Number Theory Pythagorean Triples Tesseract 4-Square Identity diophantine Equation
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A Variant of Fermat’s Diophantine Equation
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作者 Serdar Beji 《Advances in Pure Mathematics》 2021年第12期929-936,共8页
A variant of Fermat’s last Diophantine equation is proposed by adjusting the number of terms in accord with the power of terms and a theorem describing the solubility conditions is stated. Numerically obtained primit... A variant of Fermat’s last Diophantine equation is proposed by adjusting the number of terms in accord with the power of terms and a theorem describing the solubility conditions is stated. Numerically obtained primitive solutions are presented for several cases with number of terms equal to or greater than powers. Further, geometric representations of solutions for the second and third power equations are devised by recasting the general equation in a form with rational solutions less than unity. Finally, it is suggested to consider negative and complex integers in seeking solutions to Diophantine forms in general. 展开更多
关键词 Variant of Fermat’s Last Equation Positive Integer Solutions of New Fermat-Type equations Geometric Representations for Solutions of New diophantine equations
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On Diophantine Equation X(X+1)(X+2)(X+3)=14Y(Y+1)(Y+2)(Y+3) 被引量:2
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作者 段辉明 郑继明 《Journal of Southwest Jiaotong University(English Edition)》 2009年第1期90-93,共4页
The Diophantine equation X( X + 1 ) ( X + 2 ) ( X + 3 ) = 14Y( Y + 1 ) ( Y + 2 ) ( Y + 3 ) still remains open. Using recurrence sequence, Maple software, Pell equation and quadraric residue, this pap... The Diophantine equation X( X + 1 ) ( X + 2 ) ( X + 3 ) = 14Y( Y + 1 ) ( Y + 2 ) ( Y + 3 ) still remains open. Using recurrence sequence, Maple software, Pell equation and quadraric residue, this paper proved it has only two positive integer solutions, i. e., (X,Y) = (5,2) ,(7,3). 展开更多
关键词 Integer solution diophantine equation Recurrent sequence Quadratic residue
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Complete solution of the diophantine equation A^2x^4-By^2=1 and some related problems 被引量:1
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作者 曹珍富 《Journal of Harbin Institute of Technology(New Series)》 EI CAS 2001年第2期108-110,共3页
We prove that diophantine equation in title has at most one positive integer solution for any positive integers A>1, B>1. It follows that Lucas problem is very simple to solve and a recent result of Bennett ... We prove that diophantine equation in title has at most one positive integer solution for any positive integers A>1, B>1. It follows that Lucas problem is very simple to solve and a recent result of Bennett is very simple to prove. 展开更多
关键词 quartic diophantine equation COMPUTER C++
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Heron Triangle and Diophantine Equation
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作者 YANG Shi-chun MA Chang- wei 《Chinese Quarterly Journal of Mathematics》 CSCD 北大核心 2005年第3期242-246,共5页
In this paper, we study the quantic Diophantine equation (1) with elementary geometry method, therefore all positive integer solutions of the equation (1) are obtained, and existence of Heron triangle whose median... In this paper, we study the quantic Diophantine equation (1) with elementary geometry method, therefore all positive integer solutions of the equation (1) are obtained, and existence of Heron triangle whose median lengths are all positive integer are discussed here. 展开更多
关键词 quantic diophantine equation positive integer solution Heron triangle MEDIAN
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A New Proof of Diophantine Equation ■
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作者 ZHU HUI-LIN 《Communications in Mathematical Research》 CSCD 2009年第3期282-288,共7页
By using algebraic number theory and p-adic analysis method, we give a new and simple proof of Diophantine equation (^n2) = (^m4)
关键词 binomial diophantine equation fundamental unit FACTORIZATION p-adic analysis method
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On the Diophantine Equation y^2= px(x^2+ 2)
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作者 WANG Xiao-ying 《Chinese Quarterly Journal of Mathematics》 CSCD 2009年第4期499-503,共5页
For any fixed odd prime p, let N(p) denote the number of positive integer solutions (x, y) of the equation y^2 = px(x^2 + 2). In this paper, using some properties of binary quartic Diophantine equations, we pro... For any fixed odd prime p, let N(p) denote the number of positive integer solutions (x, y) of the equation y^2 = px(x^2 + 2). In this paper, using some properties of binary quartic Diophantine equations, we prove that ifp ≡ 5 or 7(mod 8), then N(p) = 0; ifp ≡ 1(mod 8), then N(p) 〈 1; if p〉 3 andp ≡ 3(rood 8), then N(p) ≤ 2. 展开更多
关键词 cubic and quartic diophantine equation number of solutions upper bound 2000 MR Subject Classification: 11D25
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The Odd Solutions of Equations Involving Euler-Like Function
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作者 Jiaxin Wu Zhongyan Shen 《Advances in Pure Mathematics》 2021年第5期440-446,共7页
<span style="white-space:nowrap;"><em><span style="white-space:nowrap;"><span style="white-space:nowrap;"><span style="white-space:nowrap;"><spa... <span style="white-space:nowrap;"><em><span style="white-space:nowrap;"><span style="white-space:nowrap;"><span style="white-space:nowrap;"><span style="white-space:nowrap;"><span style="white-space:nowrap;"><span style="white-space:nowrap;">φ</span></span></span></span></span></span><sub>e</sub></em>(<em>n</em>) </span>is a function similar to Euler function <em><span style="white-space:nowrap;"><span style="white-space:nowrap;"><span style="white-space:nowrap;"><span style="white-space:nowrap;"><span style="white-space:nowrap;">φ</span></span></span></span></span></em>(<em>n</em>). We discussed and obtained all the odd solutions of the equations <em style="white-space:normal;"><span style="white-space:nowrap;">φ<sub>e</sub></span></em><span style="white-space:nowrap;">(<em>xy</em>) </span><span style="white-space:nowrap;">= <em style="white-space:normal;"><span style="white-space:nowrap;">φ<sub>e</sub></span></em><span style="white-space:nowrap;"><sub></sub>(<em>x</em>)</span></span><span style="white-space:nowrap;"> + </span><span style="white-space:nowrap;">2</span><em style="white-space:normal;"><span style="white-space:nowrap;"><em style="white-space:normal;"><span style="white-space:nowrap;">φ<sub>e</sub></span></em></span></em><span style="white-space:nowrap;"><span style="white-space:nowrap;"><sub></sub>(</span></span><em style="white-space:normal;"><span style="white-space:nowrap;"><em style="white-space:normal;"><span style="white-space:nowrap;">y)</span></em></span></em>, <em style="white-space:normal;"><span style="white-space:nowrap;">φ<sub>e</sub></span></em>(<em>xy</em>) = 2<em style="white-space:normal;"><span style="white-space:nowrap;">φ<sub>e</sub></span></em><sub></sub>(<em>x</em>) + 3<em style="white-space:normal;"><span style="white-space:nowrap;"><em style="white-space:normal;"><span style="white-space:nowrap;">φ<sub>e</sub></span></em></span></em><sub></sub>(<em style="white-space:normal;"><span style="white-space:nowrap;">y) </span></em>and <em style="white-space:normal;"><span style="white-space:nowrap;">φ<sub>e</sub></span></em><span style="white-space:normal;">(</span><em style="white-space:normal;">xyz</em><span style="white-space:normal;">) = </span><em style="white-space:normal;"><span style="white-space:nowrap;">φ<sub>e</sub></span></em><sub style="white-space:normal;"></sub><span style="white-space:normal;">(</span><em style="white-space:normal;">x</em><span style="white-space:normal;">) + </span><em style="white-space:normal;"><span style="white-space:nowrap;"><em style="white-space:normal;"><span style="white-space:nowrap;">φ<sub>e</sub></span></em></span></em><sub style="white-space:normal;"></sub><span style="white-space:normal;">(</span><em style="white-space:normal;"><span style="white-space:nowrap;">y)</span></em> <span style="white-space:normal;">+ </span><em style="white-space:normal;"><span style="white-space:nowrap;"><em style="white-space:normal;"><span style="white-space:nowrap;">φ<sub>e</sub></span></em></span></em><sub style="white-space:normal;"></sub><span style="white-space:normal;">(</span><em style="white-space:normal;"><span style="white-space:nowrap;">z)</span></em><span style="white-space:normal;"> </span>by using the methods and techniques of elementary number theory. 展开更多
关键词 Euler-Like Function diophantine Equation Odd Solutions
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On the multiplicity of binary recurrences
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作者 董晓蕾 沈灏 《Journal of Harbin Institute of Technology(New Series)》 EI CAS 2003年第2期183-189,共7页
Let A∈N,B∈Z with gcd(A,B)=1,B{-1,0,1}. For the binary recurrence (Lucas sequence) of the form u 0=0, u 1=1, u n+2 =Au n+1 +Bu n, let N 1(A,B,k) be the number of the terms n of |u n|=k, where k∈N. In this paper, usi... Let A∈N,B∈Z with gcd(A,B)=1,B{-1,0,1}. For the binary recurrence (Lucas sequence) of the form u 0=0, u 1=1, u n+2 =Au n+1 +Bu n, let N 1(A,B,k) be the number of the terms n of |u n|=k, where k∈N. In this paper, using a new result of Bilu, Hanrot and Voutier on primitive divisors, we proved that N 1(A,B,k)≤1 except N 1(1,-2,1)=5[n=1,2,3,5,13], N 1(1,-3,1)=3, N 1(1,-5,1)=3,N 1(1,B,1)=2(B{-2,-3,-5}), N 1(12,-55,1)=2, N 1(12,-377,1)=2, N 1(A,B,1)=2(A 2+B=±1, A>1), N 1(1,-2,3)=2, N 1(A,B,A)=2(A 2+2B=±1,A>1. For Lehmer sequence, we got a similar result. In addition, we also obtained some applications of the above results to some Diophantime equations. 展开更多
关键词 binary recurrences diophantine equations MULTIPLICITIES Lucas and Lehmer sequences primitive divisors cryptographic problems
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