利用概率方法给出了形如sum from k=1 to n(1/k)>π/4(sum from k=1 to n((-1)k-1Cnk)1/(k~1/2))与sum from k=1 to n(1/k)<2~(1/2)(sum from k=1 to n((-1)k-1Cnk)1/k2)1/2的组合不等式.
文摘利用概率方法给出了形如sum from k=1 to n(1/k)>π/4(sum from k=1 to n((-1)k-1Cnk)1/(k~1/2))与sum from k=1 to n(1/k)<2~(1/2)(sum from k=1 to n((-1)k-1Cnk)1/k2)1/2的组合不等式.